Refrigeration Arithmetic: Heat Balance and COP

Refrigeration Arithmetic: Heat Balance and COP

Original quantitative learning practice in English. All 24 questions are included. Four supplied cases exercise six related calculation targets; they form one topic, not four separate tests. Every question includes the complete initial data. Use the stated model and retain intermediate precision. Choose one answer. Learning target: 20/24, not an official pass mark. This bank covers the calculation topic in its title; it is not a complete professional examination, design approval or operating instruction.
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In a supplied steady-state model, a refrigerator removes 15 kW from its cold space while consuming 3.5 kW electrical power. Heat rejected equals cooling plus power. Cooling COP equals cooling/power. It operates for 5 h. No auxiliary loads are included. Do not infer refrigerant handling or equipment settings. Calculate the heat removed over the period in kWh. Keep intermediate values unrounded; round the final result to four decimal places if necessary.